WebJun 14, 2005 · e90 be 0 1 bf 0 1 80 3c %CH% a4 75 1 4f e2 f7 89 ea0 f9 81 e9 0 1 cc is equivalent to: 90 mov si,100 93 mov di,100 96 cmp byte ptr [si],%CH% 99 movsb 9a jnz 9d 9c dec di 9d loop 96 9f mov cx,di a1 sub cx,100 a5 int 3. where %CH% is the hex value for character to be removed. Webchct10: cmp byte ptr ds:[si],0 ;end of string? jz chct90 ;if so, then done cmp al,ds:[si] ;does this char match? jnz chct20 ;if not don’t count it inc cx ;count this char chct20: inc si ;go to next char jmp chct10 ;repeat until end of str chct90: mov ax,cx ;return value in AX
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Webmov BYTE PTR [ESI], 5 ; Store 8-bit value mov WORD PTR [ESI], 5 ; Store 16-bit value mov DWORD PTR [ESI], 5 ; Store 32-bit value ... In general, PTR operator forces expression to be treated as a pointer of specified type: .DATA num DWORD 0 .CODE mov ax, WORD PTR [num] ; Load a word-size value from a DWORD ... Webcmp byte ptr [bx+1],' ' ;must specify file name jnz drvok cmp byte ptr [bx],0 ;or drive specifier jnz drvok noname: mov dx,offset dg: drverr call print jmp int_23 drvok: push ds mov dl,drive inc dl mov ah,GET_DPB int bdos mov ax,word ptr [bx+2] ;get physical sector size
Web东南微机接口第二章微型计算机指令系统续.pdf 7页 WebAug 7, 2024 · Then you should be able to see the value of that address that is "EDI+5" as a byte value. When you are ready to step select the "debug" menu then "step" or press F7; this will also allow you to see if it jumps or not. Then to run the game again you can select "run" in the debug menu, or press F9.
WebDec 8, 2024 · 汇编语言中,CMP BX,'$',与cmp byte ptr[bx],'$' 我写CMPBX,'$',debug里显示是把bx和+24比较,但是用cmpbyteptr[bx],'$',debug里就显示把bx和24比较,这是为 … Webpush si push ds push cs pop ds mov byte ptr nz,0 push ax lea si,divarr mov cx,5 @1: pop ax mov dx,0 mov bx,[si] div bx push dx cmp al,0 jne @2 cmp byte ptr nz,1 je @2 cmp cx,1 je @2 mov dl,20h jmp @3 @2: add al,30h mov dl,al
Webmov cx,0 mov cl,buf[1] lea si,buf[2] l: cmp byte ptr [si],'a' jne m mov byte ptr [si],'b' m: inc si loop l data ends code segment assume cs:code,ds:data start: mov ax,data mov ds,ax mov bx,offset buf ;指针指向待显示字符串尾部 again: mov ah,01 ;输入字符 int 21h cmp al,0dh ;是回车吗 je disp ;是,转显示 inc output[19] jmp ...
WebCMP BYTE PTR [SI+2],0 JZ validate_malformed ; NUL path (just d:) validate_loop: LODSB validate_loop1: IF KANJI invoke TESTKANJ JZ NOTKANJ6 INC SI JMP validate_loop ... MOV BYTE PTR [SI.dpb_dir_text],0 current_move: ADD SI,dpb_dir_text MOV CX,DIRSTRLEN current_loop: LODSB STOSB OR AL,AL LOOPNZ current_loop … drugs and cosmetics rules 1945 schedulesWebDec 14, 2024 · This section contains the annotated disassembly example. Functions which use the ebp register as a frame pointer start out as follows: dbgcmd. HRESULT CUserView::CloseView (void) SAMPLE!CUserView__CloseView: 71517134 55 push ebp 71517135 8bec mov ebp,esp. This sets up the frame so the function can access its … combined tenancy bcWeblds si, sbuffer ; Point DS:SI at source buffer: mov bx,0: mov ah,0 ; Be sure AH is clean: cld: looptop: mov al,BYTE PTR [ds:si] ; Get runlength byte: and al,128 ; Repeat run or random run? jz randrun ; If random run, skip ahead: mov al,BYTE PTR [ds:si] ; Else get runlength byte again: and al,127 ; Remove high bit of count: inc si ; Point to ... drugs and cosmetics act 1940 in hindihttp://www.linux-commands-examples.com/cmp drugs and cosmetics rule 1945Weblea si,buf1+2. again: cmp byte ptr [si],' ' jnz t1. inc num1 t1: inc si loop again pop cx. lea si,buf1+2 again1: cmp byte ptr [si],'a' jnz t. inc num2 t: inc si. loop again1. mov dl,10 mov al,num1. mov ah,0. div dl or ax,3030h. mov word ptr buf3+7,ax. mov al,num2 mov ah,0. div dl. or ax,3030h. 上一页 第2页 下一页 combined testingWebcmp byte ptr [DI],0 jnz CHKSWTCHES mov dx,offset trangroup:BADCD cmp byte ptr [DI-2],':' jnz CERROR4J ; Trailing '/' error mov [bp.ISDIR],2 ; Know destination is d:/ or … combined theory of hurvich and jamesonWeb汇编语言程序设计实验教程第二章实验报告.pdf,汇编语言程序设计实验教程第二章 实验报告 实验2.1 用表格形式显示字符 1.题目:用表格形式显示ascii 字符smascii 2 .实验要求: 按 15 行*16 列的表格形式显示ascii 码为 10h-100h 的所有字符,即以行为主的顺 序及 ascii 码递增的次序依次显示对应的字符。 combined testing centre